Select all that are True. O The successive ionization energies (in a hypothetica
ID: 878594 • Letter: S
Question
Select all that are True. O The successive ionization energies (in a hypothetical unit) for an unknown element are IE1 180; IE2 250; IE3 350; IE4 1800. The possible identity of the element is A O The first ionization energy of Br should be smaller than the first ionization energy of Ne. O The successive ionization energies (in a hypothetical unit) for an unknown element are IE1 180; IE2 250; IE3 350; IE4 1800. The possible identity of the element is S O The second ionization energy for K would be represented using the equation: K+(g) 2+ e (g)+Explanation / Answer
1 ) option 1,2,4 are true.
3rd option is wrong. because IE3 to IE4 jumps from 350 to 1800. it indicates valency 3. but Si valency 4.
si+4 is most stable. the ionisation energy should be jumps from IE4 to IE5 but not IE3 to IE4.
2)
average atomic weight = 15.9984 amu
O- 16 mass = 15.982 amu
O-17 mass = 16.994 amu
O-18 mass = 17.994 amu
average atomic weight = isotope number(O-17) x percent abundance + isotope number (O-16)x percent abundance
15.9984 = 17 x 0.031 + 16 * x
x =0.9669625
O-16 percent abundance = 96.7%
O-18 percent abundane :
total abundance = O-16 + O-17 + O-18
100 = 96.696 + 3.1 + O-18
O-18 abundance = 0.203 %
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