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Select all that are True. O The successive ionization energies (in a hypothetica

ID: 878594 • Letter: S

Question

Select all that are True. O The successive ionization energies (in a hypothetical unit) for an unknown element are IE1 180; IE2 250; IE3 350; IE4 1800. The possible identity of the element is A O The first ionization energy of Br should be smaller than the first ionization energy of Ne. O The successive ionization energies (in a hypothetical unit) for an unknown element are IE1 180; IE2 250; IE3 350; IE4 1800. The possible identity of the element is S O The second ionization energy for K would be represented using the equation: K+(g) 2+ e (g)+

Explanation / Answer

1 ) option 1,2,4 are true.

3rd option is wrong. because IE3 to IE4 jumps from 350 to 1800. it indicates valency 3. but Si valency 4.

si+4 is most stable. the ionisation energy should be jumps from IE4 to IE5 but not IE3 to IE4.

2)

average atomic weight = 15.9984 amu

O- 16 mass = 15.982 amu

O-17 mass = 16.994 amu

O-18 mass = 17.994 amu

average atomic weight = isotope number(O-17) x percent abundance + isotope number (O-16)x percent abundance

15.9984 = 17 x 0.031 + 16 * x

x =0.9669625

O-16 percent abundance = 96.7%

O-18 percent abundane :

total abundance = O-16 + O-17 + O-18

100 = 96.696 + 3.1 + O-18

O-18 abundance = 0.203 %

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