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the concentration of solution A is 10 mg/liter Solution A1 was made by taking 5.

ID: 878608 • Letter: T

Question

the concentration of solution A is 10 mg/liter Solution A1 was made by taking 5.00 ml of Solution A and diluting to 100.00 ml with water. Solution A2 was made by taking 10.00 ml of Solution A and diluting to 100.00 ml with water. Solution A3 was made by taking 15.00 ml of Solution A and diluting to 100.00 ml with water. Solution A4 was made by taking 20.00 ml of Solution A and diluting to 100.00 ml with water. Calculations: Determine the concentrations of Allura Red in Solutions A1, A2, A3, and A4, based on its concentration in Solution A. Record these values in your data section. Include sample calculations, using significant figures and units.

Explanation / Answer

Solution-

Concentration of solution A (M1) = 10 mg/liter        (stock solution)

a) Solution A1 was made by taking 5.00 mL of solution A and diluting to 100.00 mL with water

(M1) = 10 mg/liter        (stock solution)

V1 = 5.00 mL

V2 = 100.00 mL

M2 =?

By using dilution law

M1V1 = M2V2

10 mg/liter x 5.00 mL = M2 X 100.00 mL

M2 = 50/100 = 0.5 mg/litre

Concentration of solution A1 = 0.5 mg/litre     

b) Solution A2 was made by taking 10.00 mL of solution A and diluting to 100.00 mL with water

(M1) = 10 mg/liter        (stock solution)

V1 = 10.00 mL

V2 = 100.00 mL

M2 =?

By using dilution law

M1V1 = M2V2

10 mg/liter x 10.00 mL = M2 X 100.00 mL

M2 = 100/100 = 1 mg/litre

Concentration of solution A2 = 1 mg/litre     

c) Solution A3 was made by taking 15.00 mL of solution A and diluting to 100.00 mL with water

(M1) = 10 mg/liter        (stock solution)

V1 = 15.00 mL

V2 = 100.00 mL

M2 =?

By using dilution law

M1V1 = M2V2

10 mg/liter x 15.00 mL = M2 X 100.00 mL

M2 = 150/100 = 1.5 mg/litre = 1.50 mg/litre      

Concentration of solution A3 = 1.50 mg/litre     

d) Solution A4 was made by taking 20.00 mL of solution A and diluting to 100.00 mL with water

(M1) = 10 mg/liter        (stock solution)

V1 = 20.00 mL

V2 = 100.00 mL

M2 =?

By using dilution law

M1V1 = M2V2

10 mg/liter x 20.00 mL = M2 X 100.00 mL

M2 = 200/100 = 2 mg/litre

Concentration of solution A4 = 2 mg/litre