the laboratory technician accidentally mixed NaHCO3 with BaCl2•2H2O instead of K
ID: 878720 • Letter: T
Question
the laboratory technician accidentally mixed NaHCO3 with BaCl2•2H2O instead of KCl when preparing unknown mixtures for this experiment.A. How would this mistake affect the calculated percentage of NaHCO3 in the mixture? Justify with an explanation.
B. Is it still possible to determine the percentage of NaHCO3 in the mixture given the error made by the lab technician? Justify your answer with an explanation. the laboratory technician accidentally mixed NaHCO3 with BaCl2•2H2O instead of KCl when preparing unknown mixtures for this experiment.
A. How would this mistake affect the calculated percentage of NaHCO3 in the mixture? Justify with an explanation.
B. Is it still possible to determine the percentage of NaHCO3 in the mixture given the error made by the lab technician? Justify your answer with an explanation. the laboratory technician accidentally mixed NaHCO3 with BaCl2•2H2O instead of KCl when preparing unknown mixtures for this experiment.
A. How would this mistake affect the calculated percentage of NaHCO3 in the mixture? Justify with an explanation.
B. Is it still possible to determine the percentage of NaHCO3 in the mixture given the error made by the lab technician? Justify your answer with an explanation.
Explanation / Answer
A.
When NaHCO3 reacts with KCl, no precipitate is formed since Ksp of K2CO3 is very high but when NaHCO3 reacts with BaCl2.2H2O, it forms precipitate BaCO3 and hence percentage of NaHCO3 in mixture will be wrong (decreased)
For your reference their Ksp values are:
K2CO3 : 2130
BaCO3 : 1.03*10^-8
source: http://www.saltlakemetals.com/SolubilityProducts.htm
B.
You can still calculate the percentage of NaHCO3 by titration but percentage will not be accurate.
There are many ways to answer this question. Mine is just onw of them.
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