Calculate each of the following quantities for an ideal gas. Part A Calculate th
ID: 879336 • Letter: C
Question
Calculate each of the following quantities for an ideal gas.
Part A
Calculate the volume of the gas, in liters, if 1.70 mol has a pressure of 1.21 atm at a temperature of -5 C.
Express the volume in liters to three significant digits.
Part B
Calculate the absolute temperature of the gas at which 3.53×103 mol occupies 448 mL at 755 torr .
Express the temperature in kelvins to three significant digits.
Part C
Calculate the pressure, in atmospheres, if 2.55×103 mol occupies 413 mL at 139 C.
Express the pressure in atmospheres to three significant digits.
Part D
Calculate the quantity of gas, in moles, if 126 L at 50.0 C has a pressure of 11.35 kPa .
Express the amount in moles to three significant digits.
Explanation / Answer
We would be using the relation for ideal gas,
PV = nRT
Part A. Calculate the volume of the gas, in liters, if 1.70 mol has a pressure of 1.21 atm at a temperature of -5 C
Given.
n = 1.70 mols
P = 1.21 atm
Temperature = -5oC = 273 - 5 = 268 K
R = 0.08206 L.atm/mol.K
Feed the values,
V = 1.70 x 0.08206 x 268 / 1.21 = 30.898 L = 30.9L [three significant figures]
Part B. Calculate the absolute temperature of the gas at which 3.53×103 mol occupies 448 mL at 755 torr
n = 3.53×103 mol
P = 755 torr = 0.99342 atm
V = 448 mL = 0.448 L
Feed the values,
T = 0.99342 x 0.448 / 3.53×103 x 0.08206 = 1536.401 K = 1540K [three significant figures]
Part C. Calculate the pressure, in atmospheres, if 2.55×103 mol occupies 413 mL at 139 C.
n = 2.55×103 mol
V = 413 mL = 0.413 L
T = 139 C = 139 + 273 = 412 K
Feed the values,
P = 2.55×103 x 412 x 0.08206 / 0.413 = 0.209 atm [three significant figures]
Part D. Calculate the quantity of gas, in moles, if 126 L at 50.0 C has a pressure of 11.35 kPa
P = 11.35 kPa = 0.112 atm
T = 50 oC = 50 + 273 = 323 K
V = 126 L
Feed the values,
n = 0.112 x 126 / 0.08206 x 323 = 0.532 mol [three significant figures]
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