Consider the reaction 2ch4(g)+3O2(g)+2NH3(g)-->2HCN(g)+6H2O(g) if 416.3g NH3 is

Question

Consider the reaction 2ch4(g)+3O2(g)+2NH3(g)-->2HCN(g)+6H2O(g) if 416.3g NH3 is reacted with excess CH4 and O2 what mass of HCN can be produced? Please show conversion work Consider the reaction 2ch4(g)+3O2(g)+2NH3(g)-->2HCN(g)+6H2O(g) if 416.3g NH3 is reacted with excess CH4 and O2 what mass of HCN can be produced? Please show conversion work Consider the reaction 2ch4(g)+3O2(g)+2NH3(g)-->2HCN(g)+6H2O(g) if 416.3g NH3 is reacted with excess CH4 and O2 what mass of HCN can be produced? Please show conversion work

Explanation / Answer

since CH4 and HCN have same stotiometric coefficients i.e 2 , same moles of both will be formed. moles of CH4 = moles of HCN . moles of CH4 are 416.3/17 = 24.48 so 24.48 moles of HCN will be formed which have mass= 24.48 x 27 = 661.18gr

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