Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

One person in the group, weighing by difference, transfers 201.5 mg of pure SA i

ID: 879696 • Letter: O

Question

One person in the group, weighing by difference, transfers 201.5 mg of pure SA into a 250 mL beaker. They then add 10 mL of ethanol and wait for the solid SA to dissolve completely. At that point they add 150 mL of water. This solution is transferred quantitatively ( a funnel can be used) into a 250.0 mLvolumetric flask. The 250 mL beaker should be rinsed a few times with water, and the rinse water also added to the volumetric flask. After mixing, water is added up to the 250.0 mL line.

The resulting solution is called Solution 1. What is the concentration (mmol/mL) of Solution 1 ?

Use 138.1 g/mol as the molar mass of SA.

Explanation / Answer

Concentration = (weight / molar mass) x (1000/total volume)

from the data given,

concentration or molarity = (0.2015 gram/ 138.1g/mol) x (1000 / 250ml)

= 0.0058 mol/L