At a certain temperature, 0.840 mol of SO3 is placed in a 4.50-L container. C Se

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At a certain temperature, 0.840 mol of SO3 is placed in a 4.50-L container.

C Search Q8&A; | Chegg.comDel Mar College CHEM 1 xYAt a certain temperature, x c Dwww.saplinglearning.com/ibiscms/mod/ibis/view.php?id=1834503 com × Jump to... Logout sapling learning Sapling Learning My Assignment Del Mar College-CHEM 1412-Summer15-LINDLEY Activities and Due Dates HW 16-1 Resources o 7/26/2015 1 1 :55 PM > 90.4/1007/25/2015 06:55 PM Assignment Information Available From 7/22/2015 12:00 PM Due Date: Points Possible: Grade Category: Graded Description: Policies: Gradebook #AttemptsScore Print Calculator Periadic Table Question 6 of 14 7/26/2015 11:55 PM 95 Map 100 sapling learning 95 At a certain temperature, 0.840 mol of SO3 is placed in a 4.50-L container 90 2So Homework 95 equilibrium, 0.120 mol of O2 is present. Calculate Kc You can check your answers. You can view solutions when you complete or give up on any question. Number You can keep trying to answer each question until you get it right or give up. You lose 5% of the points available to each answer in your question for each incorrect attempt at that answer 10 98 Help With This Topic Web Help &Videos; Technical Support and Bug Reports 12 98 13 95 9:31 AM 7/26/2015

Explanation / Answer

when this equilibrium shifts to the right, forming "X" mol of O2
2SO3(g)    --->    2SO2(g) + O2(g)
0.840 - 2X ----> 2X    X

since X = 0.120
this becomes
0.600 <=>   0.240    0.120

find moles / litre:
(0.600) / 4.5L ----> 0.240 / 4.5L 0.120 / 4.5 L

which gives these molarities:
2SO3(g) --->    2SO2(g) + O2(g)
[0.133]        -->       [0.0533]    [0.0266]

Kc = [SO2]^2 [O2] / [SO3]^2

Kc = [0.0533]^2 [0.0266] / [0.133]^2

Kc = (0.0028) [0.0266] / [(0.0177)

Kc = 0.0042

Kc=4.2*10^-3

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