Help please Lead poisoning is particularly insidious because it may result from
ID: 881839 • Letter: H
Question
Help please Lead poisoning is particularly insidious because it may result from a gradual accumulation of lead ion from an unexpected source. Cases of slow poisoning from lead pigments in unglazed ceramic water vessels are not uncommon. How much lead (AW=207.1), in milligrams, would be ingested by a person drinking 1.00 liter of water a day for 4 years from a ceramic water jug whose ?chrome-yellow? pigment (PbCrO4), unprotected by glaze, has saturated all the water stored in it? (Ksp for PbCrO4 = 1.8 x 10^-14)Explanation / Answer
Solution :-
Given data ksp of PbCrO4 =1.8E-14
Molar mass of lead = 207.1 g per mol
Person drinking 1 L waterper day for 4 years
Mass of Pb ingested by person = ? mg
Lets write the ksp equation of the PbCrO4
PbCrO4 ---------- > Pb^2+ + CrO4^2-
x x
Now lets calculate the molar solubility of the PbCrO4 using the ksp vaue
Ksp = [Pb^2+] [CrO4^2-]
1.8E-14 = [x][x]
1.8E-14 = x^2
Taking square root of both sides we get
1.34E-7 = x
Therefore molar solubility of the PbCrO4 is 1.34E-7 mol per Liter
Now lets calculate the total amount of water drunken by the person in 4 years
(4 years * 365 days / 1 year ) *(1 liter / 1 day) = 1460 L
Now lets calculate the moles of the PbCrO4 drunken in 4 years
Moles = molarity * volume in liter
Moles of PbCrO4 = 1.34E-7 mol per L * 1460 L = 1.956E-4 mol
Now lets convert these moles to mass of the Pb^2+ ingested
(1.956E-4 mol * 207.1 g / 1 mol )*(1000 mg / 1 g ) = 40.5 mg Pb
Therefore amount of the lead ingested to person = 40.5 mg
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