A HNMR signal is observed at 225 hz downfield on a 155MHz instrument Map m sapli

Question

A HNMR signal is observed at 225 hz downfield on a 155MHz instrument Map m sapling learning A 1H NMR signal is observed at 225.0 H2(downfield of TMS) on a 155-MHz instrument. a) What is the observed chemical shift in parts per million (ppm)? Number ppm b) What is the chemical shift, in parts per miltion (ppm), if the sample is analyzed with a 60.0-MHz instrument? Number ppm c) Where will he proton signal appear, in hertz, if the sample is analyzed with a 60.0-MHz instrument? c) Where will the proton signal appear, in he Number Exit Previous Give Up & View Solution 0 Check Answer 0 Next Hint

Explanation / Answer

a. chemical shift = 225 Hz / 155 Mz = 1.64 ppm

b. chemical shift = 255 Hz / 60 Hz = 4.25 ppm

c. 1st chemical shift will be calculated so chemical shift is = 225/60 = 4.25 ppm now

ppm * instrument frequency = 4.25 *155 = 658.75 hz

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