1. A chromoly (a 41xx series steel) steel ball bearing weighs 4.516 grams. It co
ID: 883852 • Letter: 1
Question
1. A chromoly (a 41xx series steel) steel ball bearing weighs 4.516 grams. It contains the following components by weight 0040% Sulfur 010% Silicon 0.035% Phosphorus 0.50% Manganese 0.30% Carbon 0.20 % Molybdenum 0.95% Chromium 91.775% Iron Determine how many atoms are in the ball bearing. 2. Assume the alloy in problem 1 has an even distribution of all of the alloying elements. If we created a new ball bearing by removing 10 sextillion atoms from the original ball bearing (a) how much would the remaining chromium in the new ball bearing weigh? (b) how much would the new ball bearing weigh? 3. You can accelerate electrons by placing them between charged plates (often used in electron microscopes), consider an electron between two plates with a 50.0 volt charge across the plates, determine the wavelength associated with the electron with a mass of 9.11 x 10^-31 kg. moving at a speed of 4.19 x 10^6 m/s. 4. What is the ionization energy in electron volts for a hydrogen electron in the ground state?Explanation / Answer
1. Iron atoms = (97.75/55.845)*6.023*10^23 = 1.0*10^24
Sulfur = (0.04/32)*6.023*10^23 = 7.52875*10^20
silicon =(0.2/28) *6.023*10^23 = 4.302*10^21
phosphorus = (0.035/31)*6.023*10^23 = 6.8*10^20
manganese = (0.5/54.938045)*6.023*10^23 = 5.481*10^21
carbon = (0.3/12)*6.023*10^23 = 1.5*10^22
Chromium = (0.95/51.9961)*6.023*10^23 = 1.1*10^22
molybdenum = (0.2/95.94)*6.023*10^23 = 1.25*10^21 atom
Total atoms = 1.04*10^24 atoms
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