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I NEED EVERY PART OF THIS EVEN THE EXCEL GRAPH USE KELVIN FOR ALL TEMP 3. Triose

ID: 885530 • Letter: I

Question

I NEED EVERY PART OF THIS

EVEN THE EXCEL GRAPH USE KELVIN FOR ALL TEMP

3. Triose phosphate isomerase catalyzes a middle step in glycolysis (aka Embden-Meyerhof pathway) to interconvert the two halves of glucose after it is split: dihydroxyacetone-phosphate2 (DHAP) ! glyceraldehyde-3-phosphate2 (G3P) Only glyceraldehyde-3-phosphate can enter the next step of the pathway. AG degree' at 25 degree C for this reaction is +7.56 kJ/mol. Assume 25 degree C in answering the following questions: a. Does the AG degree ' favor glyceraldehyde-3-phosphate2 formation?? Explain. b. What is Keq' for this reaction?? e. What ratios of [glyceraldehyde-3-phosphate2]/[dihydroxyacetone-phosphate2] would favor the forward reaction? d. In vivo concentrations in human erythrocytes are 0.14 mM dihydroxyacetone-phosphate2 and 0.0 19 mM glyceraldehyde-3-phosphate2. Do these concentrations drive the isomerization in a forward direction?? Explain. If the answer is no, how can glycolysis proceed? e. Use Excel to plot AG? as a function of the [G3P]/[DHAP] ratio, changing the ratio in 10-fold increments over the range Keq x i0 to Keq x 10^3. Starting at equilibrium, how much does triangle G' change for each 10-fold decrease in the ratio [G3PJ/[DHAP]? Again starting at equilibrium, how much does it change for a 10-fold increase in the ratio?

Explanation / Answer

a) Since delta G0reaction > 0 ; the reaction is non-spontaneous and hence, doesnot favours the formation of glyceraldehyde-3-phosphate2-.

b) delta G0reaction = -R*T*lnKeq ; where R = Universal Gas Constant = 8.314 J/mole/kelvin ; T = temperature in kelvin

thus, 7560 = -8.314*298*lnKeq

or, lnKeq = -3.05

or, Keq = 0.047

c) for the product formation to be favoured ; delta G0 > 0

or, R*TlnKeq > 0

or, Keq > 1

Thus,

Keq = [glyceraldehyde-3-phosphate2-]/[dihydroxyacetone-phosphate2-] > 1

d) [glyceraldehyde-3-phosphate2-]/[dihydroxyacetone-phosphate2-] = (0.109)/(0.14) 0.136 < 0

hence, glycolysis cannot proceed

For glycolysis to occur, either the concentration of glyceraldehyde-3-phosphate2- is to be raised or the concentration of dihydroxyacetone-phosphate2- is to be lowered such that the ratio of the two becomes greater than 1.