1) Colligative properties depend on the... (choose all that apply) What is the v

Question

1) Colligative properties depend on the... (choose all that apply)

What is the vapor pressure in atm of a solution at 25 oC produced by dissolving 56.4 g of dextrose (C6H12O6) in 383.5 g of water? Vapor pressure of water at 25 oC = 0.0313 atm

3)

How many moles of ions are present in an ideal solution that is produced by dissolving 23.3 g of Cu(NO3)2 in 417 g of water?

Molar mass of the non-volatile solute.

Particle size of the non-volatile solute.

Mole fraction of the non-volatile solute.

Composition of solute particles.

None of the above.
2)

Molar mass of the non-volatile solute.

Particle size of the non-volatile solute.

Mole fraction of the non-volatile solute.

Composition of solute particles.

None of the above.
2)

Explanation / Answer

Solution :-

1) Colligative properties depends on the the mole fraction of the non volatile solute.

Q2 What is the vapor pressure in atm of a solution at 25 oC produced by dissolving 56.4 g of dextrose (C6H12O6) in 383.5 g of water? Vapor pressure of water at 25 oC = 0.0313 atm

Solution :- Using the given mass of the each compound lets calculate moles of each

moles = mass / molar mass

moles of dextrose = 56.4 g /180.15 g per mol =0.3131 mol

moles of water = 383.5 g / 18.0148 g per mol = 21.3 mol

now lets calculate the mole fraction of the water

mole fraction of water = moles of water / total moles

                                        = 21.3 mol / (21.3 mol +0.3131 mol)

                                        = 0.9855

now lets calculate the vapor pressure of the solution

Vapor pressure of the solution = mole fraction of solvent * vapor pressure of pure solvent

                                                       = 0.9855 * 0.0313 atm

                                                       = 0.0308 atm

Therefore vapor pressure of solution = 0.0308 atm

Q3 How many moles of ions are present in an ideal solution that is produced by dissolving 23.3 g of Cu(NO3)2 in 417 g of water?

Solution :-

Lets first calculate the moles of the Cu(NO3)2

23.3 g / 187.56 g per mol = 0.1242 mol Cu(NO3)2

Now lets convert moles of Cu(NO3)2 to to the moles of total ions

1 mole Cu(NO3)2 = 3 mole ions

0.1242 mol Cu(NO3)2 * 3 mol ions / 1 mol Cu(NO3)2 = 0.373 mol ions.

Therefore total moles of ions = 0.373 mol ions

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