how to do part C 2-43. A chemical reaction A B is carried out in a closed vessel
ID: 885757 • Letter: H
Question
how to do part C 2-43. A chemical reaction A B is carried out in a closed vessel. The following data are taken for the concentration of A. CA(e/L.), as a function of time, r(min), from the start of the reaction: min) tmin) 36 65100160 Caeniter) 0.18230.1453 0.1216 0.1025 0.0795 0.079500495 A proposed reaction mechanism predicts that Ca and i should be related by the expression CA-CA In where k is the reaction rate constant. (a) Do the data support this prediction? If so, plot the data appropriately to determine the value of k (b) If the tank volume is 125 L and there is no B in the tank at t = 0, how much B(g) does the tank contain after two hours? (e) Estimate the time required for the final concentration of A to reach 1.1. 1.05, and 1.01 times Che, and determine the mass of B produced at each of these conditions for the reactor described in Part (b)Explanation / Answer
Answer:It is a first order reaction.
Rate constant (K) = [2.303/t]*log(a/a-x)
Given:
At time t = 0 min
a = 0.1823
At time t = 3 min
a-x = 0.1453
thus,
K = [2.303/36]*log(0.1823/0.1453)
K = 0.0063
Let the Time required ro reach infinity concentration = t1.
infinity concentration = 0.0495
K = [2.303/t1]*log(0.1823/0.0495)
0.0063 = [2.303/t1]*(0.566)
0.0063= 1.303/t1
t1 = 1.303/0.0063
t1=206.8 min
Thus time required to reach infinity concentration is = 206.8 minutes.
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