Part A Solubility At 30.0°C, the molar solubility of barium sulfate in water is

Question

Part A Solubility At 30.0°C, the molar solubility of barium sulfate in water is 1.20x10-5 M. Calculate the solubility in grams per liter. Express your answer in grams per liter to three significant figures Learning Goal To convert between different solubility units and understand what they mean solubility 2.80x10-3 g/L The solubility of a solute is the maximum amount that can be dissolved in a given amount of solvent. As the name implies, molar solubility reports the solubility in units of molarity, M, or moles per liter However, some other common units are grams per liter (g/L) and parts per million (ppm) Submit Hints My Answers Give Up Review Part Correct Part B How many liters of water are required to dissolve 1.00 g of barium sulfate? Express your answer in liters to three significant figures. Submit Hints My Answers Give Up Review Part

Explanation / Answer

Part:B:

Given that, the solubility of BaSO4 in 1 L solution = 2.80*10-3 g

Therefore, 1 g of BaSO4 should be required the volume = (1.0 g) (1.0 L /2.80*10-3 g) = 357.1 L

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