At what temperature would a mixture of 80% cyclohexane and 20% toluene boil at?

Question

At what temperature would a mixture of 80% cyclohexane and 20% toluene boil at? What would be the approximate percent composition of the condensed vapor above this mixture? If you condensed some of this vapor:- at what temperature would it boil? - what would be the percent composition of the vapor I this case? At what temperature would a mixture of 80% cyclohexane and 20% toluene boil at? What would be the approximate percent composition of the condensed vapor above this mixture? If you condensed some of this vapor:- at what temperature would it boil? - what would be the percent composition of the vapor I this case? At what temperature would a mixture of 80% cyclohexane and 20% toluene boil at? What would be the approximate percent composition of the condensed vapor above this mixture? If you condensed some of this vapor:- at what temperature would it boil? - what would be the percent composition of the vapor I this case?

Explanation / Answer

first of all we need the boiling point of pure cyclohexane and pure toluene

Pure Cyclohexane = 80.74 *C

Pure Toluene = 110.6 *C

there the fractions are = 4/5 for cyclohexane and 1/5 for toluene

The boiling will occur at = 0.8*80.74 + .2*110.6 = 86.712*C

mole fraction of cyclohexane in vapour = (0.8*80.74)/86.712 = 0.7449

mole fraction of toluene = 0.2550

therefore the temp of the above mixture = 0.7449*80.74 + .2*0.2550 = 60.19*C

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