1) Balance the following skeletal chemical equations. (Use the lowest possible c

Question

1) Balance the following skeletal chemical equations. (Use the lowest possible coefficients.)

(a) ------- CH4(g) + ------- O2(g) ------> CO2(g) + ------- H2O(g)

(b) ----- Al(s) + ------ H2SO4 (aq)----->Al2(SO4)3(s) + ------- H2(g)

(c)------- KClO3(s) ------- > KCl(s) + ------ O2(g)

(d)----- MnO2(s) +----- HCl(aq) -----> Cl2(g) + ---- MnCl2(aq) + ---- H2O(l)

2) To prepare a fertilizer, an engineer dilutes a stock solution of sulfuric acid by adding 22.1 L of 3.00 M acid to enough water to make 500. L. What is the mass of sulfuric acid per milliliter of the diluted solution?
- g

3) Propane (C3H8) is widely used in liquid form as a fuel for barbecue grills and camp stoves. For 67.8 g of propane, determine the following.

(a) Calculate the moles of compound.
- mol
(b) Calculate the grams of carbon.
- g

Explanation / Answer

(a) CH4(g) + O2(g) ------>   CO2(g) + H2O(g)

(b) 2 Al(s) + 3 H2SO4 (aq)-----> Al2(SO4)3(s) + 3 H2(g)

(c) 2KClO3(s) ------- > 2KCl(s) + 3 O2(g)

(d) MnO2(s) + 4HCl(aq) -----> Cl2(g) + MnCl2(aq) + 2H2O(l)

2) M1V1 = M2V2

3*22.1 = 500*M2

M2 = 3*22.1/500 = 0.1326 M

mass of H2so4 = v in L * M* Mwt = (1/1000)*( 0.1326)*98

   = 0.013 grams/ml

3) a) No of moles of propane = wt/mwt = 67.8/44.1 = 1.54 mole

molarmass of C3H8 = 44.1 g/mol

b) 1mole C3H8 = 36 grams carbon

1.54 mole C3H8 = 36*1.54/1 = 55.44 grams carbon

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