Exercise 4.65 Consider the following precipitation reaction: 2Na3PO4( a q )+3CuC

Question

Exercise 4.65

Consider the following precipitation reaction: 2Na3PO4(aq)+3CuCl2(aq) Cu3(PO4)2(s)+6NaCl(aq)

Part A

What volume of 0.189 M Na3PO4 solution is necessary to completely react with 87.5 mL of 0.115 M CuCl2?

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General Chemistry - Chem 50

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Chapter Four Homework

Exercise 4.65

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Exercise 4.65

Consider the following precipitation reaction: 2Na3PO4(aq)+3CuCl2(aq) Cu3(PO4)2(s)+6NaCl(aq)

Part A

What volume of 0.189 M Na3PO4 solution is necessary to completely react with 87.5 mL of 0.115 M CuCl2?

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Explanation / Answer

2Na3PO4(aq) + 3CuCl2(aq) -----------------> Cu3(PO4)2(s) + 6NaCl(aq)

Molarity   ( M1 )= 0.189 M

volume of Na3PO4    ( V1) = ??

moles of Na3PO4   (n1) = 2

volume of CuCl2 (V2) = 87.5 mL

Molarity of CuCl2 (M2)= 0.115 M

moles of Na3PO4 ( n2) = 3

formula : M1V1 / n1 = M2V2 / n2

0.189 x V1 / 2 = 0.115 x 87.5 /3

V1 = 35.5 mL

volume of Na3PO4 = 35.5 mL

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