1) Prepare 250mL of a 0.35 M solution of hydrochloric acid. Concentrated hydroch
ID: 889266 • Letter: 1
Question
1) Prepare 250mL of a 0.35 M solution of hydrochloric acid. Concentrated hydrochloric acid comes from the chemical companies as a 12 M liquid. How much (in mL) of this 12 M solution will be needed to dilute to 250 mL to get the desired 0.35 M solution.
2) Dilute sodium phosphate solution. First add 21 mL of a 1.5 M solution to a 250 mL volumetric flask then fill the flask with H2O to the 250 mL mark. What is the resulting concentration of sodium phosphate in Molarity?
Please show work of how you got to the final answer. Thank you!
Explanation / Answer
(1) According to the dilution principle,
M1V1 = M2V2
Given that, M1 = 12 M , V1 = ?
M2 = 0.35 M , V2 = 250 mL
=> V1 = M2V2 / M1
=> V1 = 0.35 x 250 / 12 = 7.29 mL
=> V1 = 7.29 mL
(2) M1V1 = M2V2
Given that, M1 = 1.5 M , V1 = 21 mL
M2 = ? , V2 = 250 mL
=> M2 = M1V1/V2 = 1.5 x 21 / 250
=> M2 = 0.126 M
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