NaHCO3 is one of the oldest antacids used. use the stoichiometry of the reaction

Question

NaHCO3 is one of the oldest antacids used. use the stoichiometry of the reaction above to predict a theoretical value for the acid neutralizing capacity of NaHCO3 in mmol H+ per gram of antacid. HCO3 + H --> H2O + CO2 NaHCO3 is one of the oldest antacids used. use the stoichiometry of the reaction above to predict a theoretical value for the acid neutralizing capacity of NaHCO3 in mmol H+ per gram of antacid. HCO3 + H --> H2O + CO2 NaHCO3 is one of the oldest antacids used. use the stoichiometry of the reaction above to predict a theoretical value for the acid neutralizing capacity of NaHCO3 in mmol H+ per gram of antacid. HCO3 + H --> H2O + CO2

Explanation / Answer

Solution :-

Balanced reaction equation is as follows

HCO3^- + H^+ --> H2O + CO2

We need to find the moles of the 1 g NaHCO3

moles = mass / molar mass

molar mass of NaHCO3 = 84.007 g per mol

moles of NaHCO3 = 1 g / 84.007 g per mol = 0.0119 mol NaHCO3

Now lets calculate the moles of the H^+ using the mole ratio of the NaHCO3 and H^+

mole ratio is 1 : 1

Therefore moles of the H+ react with the 0.0119 mol NaHCO3 are same

so moles of H^+ = 0.0119 mol

now lets convert moles to millimoles (mmol)

0.0119 mol H^+ * 1000 mmol / 1 mol = 11.9 mmol H^+

So the 1 g of the NaHCO3 can neutralize 11.9 mmol H^+

Hence capacity of the NaHCO3 to neutralize the acid is 11.9 mmol H^+ per g of NaHCO3

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.