The thermochemical equation for the reaction between dinitrogen monoxide and oxy

Question

The thermochemical equation for the reaction between dinitrogen monoxide and oxygen to produce nitrogen dioxide is shown below. Write the thermochemical equation for the reaction when 1.00 mole of nitrogen dioxide is formed.

2 N2O(g) + 3O2(g)      4NO2(g)                             DHo = -28.0 kJ

a.     N2O(g) + 3O2(g)      NO2(g)                   DHo = -28.0 kJ

b. N2O(g) + O2(g)      NO2(g)                        DHo = -28.0 kJ

c. 2 N2O(g) + 3O2(g)      4NO2(g)                 DHo = -56.0 kJ

d. ½ N2O(g) + ¾ O2(g)      NO2(g)               DHo = -7.00 kJ

e. ½ N2O(g) + O2(g)      NO2(g)                    DHo = -14.0 kJ

Explanation / Answer

Ans: d)

It is very easy to solve this problem,

The given equation was 2 N2O(g) + 3O2(g)      4NO2(g)                             DHo = -28.0 kJ

The above equation showing that 4 moles of NO2 (g) formation

in order to get 1 mole, let us divide the equation by 4 both sides , we will get

½ N2O(g) + ¾ O2(g)      NO2(g)               DHo = -7.00 kJ

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