C WWW sapling learning.com /ibiscms/mod/ibis/view.php?id-1960325 Sapling Learnin

Question

C WWW sapling learning.com /ibiscms/mod/ibis/view.php?id-1960325 Sapling Learning Northwestern Oklahoma State University CHEM 1115 5 WICKHAM Activities and Due Dates HW 3 My Assignment O 9/30/2015. 11:55 PM A 33/100 O 9/30/2015 02:58 AM Gradebook Attempts Print Calculator Periodic Table 00 Questi 7 of 67 Combining 0.219 mol of Fe203 with excess carbon produced 1 g of Fe Fe,O 3C 2Fe +3CO What is the actual yield of Number mol What was the theoretical yield of iron in moles? Number mol What was the percent yield? Previous Give Up & View Solution Check Answer Next Exit C) Chapter 5 ppt C) Chapter 3 ppt Chapter 2 (2).pptx Chapter 4.pptx Search the web and Window Resources Assignment Information Available From: 9/6/2015 06:00 PM 9/30/2015 11:55 PM Due Date: Points Possible: 100 Grade Category: Graded Description: Policies: Homework heck y up on any question You can keep trying to answer each question until you get it right or give up 5% e points available t o Help With This Topic Web Help & Videos O Technical Support and Bug Reports Topic 2bb (1).pptx Logo 5.29 PM 9/30/20

Explanation / Answer

The balanced equation is -

Fe2O3 + 3 C ----> 2 Fe + 3 CO

Therefore, the actual yield of iron from 0.219 mol of Fe2O3 = (17.1 g/55.5 g/mol) = 0.308 mol Fe

Theoretical yield = (0.219 mol Fe2O3) (2 mol Fe / 1 mol Fe2O3)

                           = 0.438 mol Fe

Percent yield = (0.308 mol / 0.438 mol)*100 = 70.3 %

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.