Acodofocation of sodium bicarbonate(NaHCO 3 ) produces carbon dioxide in a two-s

Question

Acodofocation of sodium bicarbonate(NaHCO3) produces carbon dioxide in a two-step process. The first step produces carbonic acid (H2CO3). Write and balance the molecular equation for the first step of the reaction of sodium bicarbonate with HF.

The second step is the decompostion of a carbonic acid to ccarbon dioxide. Write and balance the molecular equation for the second step.

Now write the overall net ionic equation for te acidification of NaHCO3 to produce CO2.

What is the molar ratio of CO2 produced to NaHCO3 decomposed?

What mass of CO2 will be produced by the complete decompostion of 1346 mg of NaHCO3?

Explanation / Answer

Lets show the mechanism in two steps.

1).

NaHCO3 (s) + HF (aq) --- > H2CO3 (aq) + NaF (aq)

2).

H2CO3 (aq) --- > H2O (l) + CO2 (g)

Lets write overall reaction

NaHCO3(s) + HF(aq) --- > H2CO3 (aq) + NaF (aq)

H2CO3 (aq) --- > H2O (l) + CO2 (g)

-------------------------------------------------------------------

NaHCO3 (s) + HF (aq) --- > NaF (aq) + H2O (l) + CO2(g)

Complete ionic reaction:

NaHCO3 (s) + HF (aq) --- > Na+ (aq) + F- (aq) + H2O (l) + CO2 (g)

Net ionic equation :

NaHCO3 (s) + HF (aq) --- > Na+ (aq) + F- (aq) + H2O (l) + CO2 (g)

Molar ratio of CO2 produced to NaHCO3 decomposed is 1 : 1

Calculation of mass of CO2 formed from 1346 mg NaHCO3

Conversion of mass of NaHCO3 = 1346 mg x 1 g / 1000 mg

= 1.346 g

Calculation of moles of NaHCO3 = 1.346 g x 1 mol / 84.0059 g

= 0.016 mol

Moles of CO2 produced = 0.016 mol x 1 mol CO2 / 1mol NaHCO3

= 0.0160 mol CO2 produced

Mass of CO2 = 0.0160 mol CO2 x 44.009 g /mol

= 705 g

Mass of CO2 produced = 0.71 g

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