lysozyme is an enzyme 10/5/2015 10:55 PM 74.8/100 G 10/3/2015 03:38 PM em Print

Question

lysozyme is an enzyme 10/5/2015 10:55 PM 74.8/100 G 10/3/2015 03:38 PM em Print 11 Caklator-Periodic Table Gradebook Question 2 of 23 Map dub Lysozyme is an enzyme that defends your body against bacterial invaders in fluids like tears, mucus, breast milk, and saliva. Lysozyme dleaves the peptid death of the bacterium. Peptidoglycan is made of long polysaccharide chains linked to each other peptides. The active site of lysozyme binds to six sugar residues, labeled A through F, and breaks the 1-4 glycosidic bond between the D and E rings. component of the bacterial cell wall, resulting in the Depicted below are the D (left side) and E (right) sugars of peptidoglycan in the absence of Note that the polysaccharide continues to both the left and right with repeats of the saccharide shown CH2 OH H2OH Please scroll down for more of this question. D ring E ring The lysozyme peptidoglycan hydrolysis reaction proceeds in two steps. In the first step, the peptidoglycan s covalently bound to the enzyme. In the second step, a water molecule is consumed and the catalytic residues of the enzyme are restored. Depicted below are two snapshots of the peptidoglycan hydrolysís reaction. The drawings show the D ring (left) and E ring (right) sugars bound in the active site of lysozyme along with the carboxylic acid groups of two catalytically important amino acids. Aspartate (Asp52, indicated by R1) is positioned below the sugars and glutamic acid (Glu35, indicated by R2) is above. For simplicity, only one pair of electrons is shown on the carboxylate ions. Add 3 curved arrows to show the electron flow in the first step of the reaction, leading to formation of the structures shown to the right (not including Add 3 curved arrows to show the electron flow in the second step of the reaction, which results in the final products and the restoration of the original charge G+ en p&View; Solution h Ran --th- ar Previous Q Check Answer O Next Exit Hint

Explanation / Answer

A water molecule in the active site act as a specific base and donate an OH- to form the NAG-OH leaving group

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.