suppose you were instructed to add 0.2 mL of sample to 9.8 mL dilutent, but inst

Question

suppose you were instructed to add 0.2 mL of sample to 9.8 mL dilutent, but instead added 2.0mL sample. What was the intended dilution and what was the actual dilution?
Please label answers suppose you were instructed to add 0.2 mL of sample to 9.8 mL dilutent, but instead added 2.0mL sample. What was the intended dilution and what was the actual dilution?
Please label answers suppose you were instructed to add 0.2 mL of sample to 9.8 mL dilutent, but instead added 2.0mL sample. What was the intended dilution and what was the actual dilution?
Please label answers

Explanation / Answer

Intended dilution is :

Let the initial concentration = c

concentration X volume = New concentration x new volume

c X 9.8 = new concentration X 10

New concentration = 0.98 c

so it is diluted 1.02 times

Actual dilution :

Let the initial concentration = c

concentration X volume = New concentration x new volume

c X 9.8 = New concentration X 11.8

New concentration = 0.83 c

so it diluted 1.2 times of initial concentration

New concentration = 0.98 c

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