que 8 and 9 with full solution Solid FA2 is a mixture of sodium carbonate, Na_2C
ID: 892474 • Letter: Q
Question
que 8 and 9 with full solution Solid FA2 is a mixture of sodium carbonate, Na_2CO_3 and sodium chloride, NaCI. 5.00 g of FA2 was dissolved in 250 cm^3 of solution in a volumetric flask. 25.00 cm63 of this solution was titrated with 0.120 M hydrochloric acid using a suitable indicator. 34.80 cm^3 of acid solution was needed for the titration. The equation for the reaction is The number of moles of sodium carbonate in the 25.00 cm^3 solution titrated The number of moles of sodium carbonate in the 250.0 cm^3 solution in the volumetric flask The mass of sodium carbonate in 1.00 g sample of FA2 and The percentage by mass of sodium chloride in FA2 (8 M) 25.0 cm^3 of a solution of 0.100 M solution of Fe^2+ (aq) reacted with 26.80 cm^3 of potassium manganate (VII) solution, KMnO_4 (aq), acidified with excess sulphuric acid. Calculate The concentration of the KMnO_4 solution in M and The mass of manganese in 1 dm^3 of the KMnO_4 solution.Explanation / Answer
Balanced equation is Na2CO3+2HCl--------à2NaCl+H2O+CO2
A)M1V1/n1=M2V2/n2
M1*25/1=(0.12*34.8)/(2*25)
M1=0.0834M
0.0834moles/lit
In 25ml=0.002moles
B)in 250ml=0.02moles
C)The mass of Na2CO3 in 1 lit=0.0843*MW=0.0843*106=8.9g this is in5g sample
In 1g sample the weight of Na2CO3=5/8.9=0.56g
Q9) M1V1/n1=M2V2/n2
(0.1*25)/5=(M2*26.8)/1=>M2=0.018M
Mass ofKMnO4=0.018*158=2.94g
Mass of Mn=0.018*52=0.936g
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