1. Silver iodate is considered insoluble and magnesium iodate is considered solu

Question

1. Silver iodate is considered insoluble and magnesium iodate is considered soluble.

The solubility product of AgIO3 is 3.1 x 10-8.

If 310.6 mL of a Mg(IO3)2 solution with a molar analytical concentration of 0.0348 M is added to 478.4 mL of an AgIO3 solution with a molar analytical concentration of 0.000152 M, how many grams of solid precipitate will form?

2. Copper (I) chloride is considered insoluble and barium chloride is considered soluble.

The Ksp for CuCl is 1.9 x 10-7.

If 324.1 mL of a BaCl2 solution with a molar analytical concentration of 0.0496 M is added to 325.4 mL of a CuCl solution with a molar analytical concentration of 0.000253M, how many grams of solid precipitate will form?

Explanation / Answer

AgIO3 <-> Ag+ and IO3- ksP = 3.1*10^-8

V1 = 310.6 ml of Mg(IO3)2

M1 = 0.0348

V2 = 478.4 ml AgIO3

M2 = 0.000152

grams of precipitate will form

In solution:

Vt = V1+V2 = 310.6+478.4 lm = 789 ml

Mg(IO3)2 --> Mg+2 and 2IO3-

AgIO3 <-> Ag+ and IO3-

There is a common ion, IO3-; this will shift equilibrium to the left (solid product AgIO3)

Find total mols of AgIO3 in solution

N2 = M2*V2 = 0.000152*478.4 = 0.0727 mol of AgIO3

Find mols in solution of of IO3

M1*V1 *2(mol per mol) = 2*310.6*0.0348 = 21.617 mol of IO3- in solution

Recalculate concentration

M3 = mol of IO3- / total volume = 21.617/789 = 0.02739

Calculate Solubility given this conditions

Ksp = [Ag+][IO3-]

3.1*10^-8 = [Ag+][IO3-]

Recall that [IO3-] = 0.02739

then

3.1*10^-8 = [Ag+][0.02739]

Solve for Ag+

[Ag+] = (3.1*10^-8) / (0.02739) = 1.13*10^-6 mol per liter of Ag+

This is the solubility of AgIO3

BUT we want precipitate so

Moles of AgIO3 in solution

N = M*V = 1.13*10^-6 * 789 = 0.000892 mol of AgIO3

Find out how much is going to precipitate

0.0727 - 0.000892 = 0.071808 mol are in excess, they will precipitate

calculat emass

MW of AgIO3 = 282.77 g/gmol

M = mol*MW = 0.071808*282.77 = 20.3 g of precipitate!

NOTE: consider posting question 2 in another set of Q&A. Wea are only allowed to answer 1 question in one single set

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.