Test Your Quantitative Ability ii. Suppose a salt and a glucose solution are sep
ID: 89284 • Letter: T
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Test Your Quantitative Ability ii. Suppose a salt and a glucose solution are separated by a membrane that is permeable to water but not to the solutes. The NaCl solution has a concentration of 1.95 g per 250 mL ofwater (molecular weight- 58.5). The glucose solution has a concentration of9.0 gper 250 mLof water (molecular wei ght 180) whether osmosis will occur and, if Calculate the molality, millimolality, and olality both solutions. State it will, in which direction. Explain your answer. Clinical Investigation Questions edema 12. What is the osmotic role of plasma albu how would a low plasma albumin level promote m, and The de Sin lau ma autom min in note maher fluid the significance of normal hy are infravendus solutions generally isotonic and not hypotonic or hypertonic in Bon and blood eew would saline? she' watan in swell upExplanation / Answer
1 ) molality = moles of solute/kilogram of solvent
molality of NaCl n=m/M
1.95g / 58.5 g/mol = ..033moles/ml
since 0.033mol per 250mL of water, then will convert into lit (multiply by 4 times) 0.033 * 4 = 0.132moles/L
molality of NaCl-0..132moles/L
Molality og Glucose-n=m/M= 9.0g / 180 = 0.05mol
ince 0.05 mol per 250mL of water then will convert into lit (multiply by 4 times) 0.05*4 = 0.20 moles/lit
molality of Glucose-0.20 moles/lit
2) millimolality= moles / 10^-3 (abbreviated mM) = a millimeter is 1/1000 (which is 10-3) of a meter
millimolality of NaCl=0.132moles/L/10-3 = 132mM
millimolality Glucose= 0.20 moles/lit / 10-3 =200mM
3)milliosmolality= millimolality * number of ions
milliosmolality of NaCl = 132mM * 2 because NaCl dissociates into 2 ions in solution: Na+ and Cl
= 264 mM
Glucose will not break apart in solution or dissociate so the millmolality and milliosmolality will be th same i.e. = 200mM
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