molar volume of H2 V/nz 8. Using student results for the class, calculate the av

Question

molar volume of H2 V/nz 8. Using student results for the class, calculate the averag value of R for the class. a. Was the class more or less accurate than you? e percent error, and standard deviation for the VII. Questions 1. A student noticed that the magnesium ribbon appeared to be oxidized- the and dull rather than silver and shiny. What effect would this error have on the m metal surface was black easured volume of hydrogen gas? Would the calculated molar volume of hydrogen be too high or too low as a result of this error? Explain. 2. One mole of hydrogen gas has a mass of 2.02 g. Use your value of the molar volume of hydrogen to calculate the mass of one liter of hydrogen gas at STP. This is the density of hydrogen in g/L. How does this experimental value of the density compare with the literature value? (Consult a chemistry handbook for the density of hydrogen.) 3. In this experiment, it was assumed that the magnesium strip was the limiting reactant. Do calculations 4. In a similar experiment, a piece of aluminum was reacted with HCI. The hydrogen gas produced was the atmospheric pressure is 762.8 mmHg, and if the to prove this. collected in a 50 mL graduate cylinder in the same way a. Write and balance the equation for this reaction. (Hint: what is the formula of aluminum chloride, the other product?) b. If 39.5 mL of Ha are produced at 21°C when height of the liquid column in the graduated cylinder is 11.2 cm, what mass of aluminum was used? total pressure of the gases contained in the gas collecting tube. What if this were not done? Explain how the value you calculated for R would be affected. 5. In this experiment, the partial pressure of water vapor and a correction factor are subtracted from the

Explanation / Answer

1)

If you find your material oxidized, it won't react enough, your mass calculation of the MAgnesium will be different (singe you are now having MgO)

The volume will be less than that of the actual one, since les is going to react, less H2 is going to be formed

Molar Volume = Volume per unit mol

If we have the same amount of moles, and less Volume, you will be having less molar volume due to this error

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