6. What is the electrophile in the Friedel-Crafts alkylation reaction with tert-
ID: 893886 • Letter: 6
Question
6. What is the electrophile in the Friedel-Crafts alkylation reaction with tert-butylchloride? A. The tert-butyl cation B. A complex of tert-butylchloride and aluminum trichloride C. A proton D. Aluminum trichloride Which of the following halides will not work as an electrophile in a Friedel-Crafts alkylation reaction? 7. Br Br A. 8. Br A. A B. B C. C D. D What are the two effects that have to be considered to determine the influence a substituent will have on electrophilic aromatic substitution? 8. A. Steric and electronic B. Inductive and steric C. Inductive and resonance D. Resonance and electronic 9. Why is the nitro group a meta director? A. Because it is sterically very large B. Because it adds electron density to the meta position, thus activating it C. Because it stabilizes the intermediate cation D. Because it removes more electron density from the ortho and para positions than the meta position, thus deactivating the meta position lessExplanation / Answer
Solution :-
Q6) When the AlCl3 reacts with the tertiary butyl chloride then it fors the tertiary cation which is the electrophile in the fridal craft alkylation
Therefore the correct answer is option ‘A’
Q7) Alkyl halide shown in the option B will not work in the fridal craft alkylation because it would be less stable and can be rearranged to form different carbocations.
Q8) The inductive effect and the resonance effect are the important effects that affects the aromatic electrophilic substitution reactions
Therefore correct answer is option ‘C’
Q9) Nitro groups (NO2^-) is the electron withdrawing group therefore it removes the electron density from the ortho and para positions than meta position therefore it is meta directing group.
Therefore correct answer is option ‘D’
Q10) The problem with the Fridal craft alkylation is that it can give overalkylated products.
Therefore option ‘C’ is the correct answer.
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