q0=? q6=? q0/q6=? Acrylonitrile can be formed from propylene, ammonia and oxygen

Question

q0=?

q6=?

q0/q6=?

Acrylonitrile can be formed from propylene, ammonia and oxygen in the reaction To produce acrylonitrile stoichiometric ratios of propylene, ammonia, and oxygen are fed into the reactor The single pass conversion of this reaction is 26.9% of the propylene. The product of the reaction is fed into a separator where the unreacted propylene, ammonia, and oxygen are recycled back to the feed stream, and the acrylonitrile and water exit as products. and hae aoryvonitie and weader exi ao rducisnmonia, and oygen are recycled back to the feed stream. qe mol/min g mol C3He/min q8 mol NH3/min qo mol O2/min qo molmin q4 mol/min q5 mol/min Reactor Separator q1 mol C3He/min q2 mol NH3/min 93 mol O2/min qo mol/min 14.6 kg C3H3N/min qn mol H2O/min

Explanation / Answer

Lets start with 14.6 kg of C3H3N required,

moles of C3H3N/min = g/mol = 14.6 kg x 1000/53.06 g/mol = 275.16 mols

moles of C3H6 required to form 275.16 mols of C3H3N would be = 275.16 mols

grams of C3H6 required = 275.16 x 42.08 = 11.58 kg [with 100% conversion]

with 26.9% conversion = actual theoretical yield required = 14.6/0.269 = 54.28 g C3H3N

moles of C3H3N (q1) = 54.28/53.06 = 1.03 mol/min

grams of C3H6 needed in reality for the process = 1.03 x 42.08 = 43.34 g

moles of NH3 required (q2) = 1.03 mol/min

moles of O2 required (q3) = 1.5 x 1.03 = 1.545 mol/min

Flow rate qo = 1.03 + 1.03 + 1.545 = 3.605 mol/min

grams of C3H3N not formed = 39.68 g

mols of C3H3N = 39.68/53.06 = 0.75 mols

Feed in recycle would be

C3H6 (q7) = 0.75 mol/min

NH3 (q8) = 0.75 mol/min

O2 (q9) = 1.13 mol/min

So, q6 = 0.75 + 0.75 + 1.13 = 2.63 mol/min

qo/q6 = 3.605/2.63 = 1.37

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