Kc at 25 degrees c for reaction a+b=ab. If 4.28x10-6 mol of a and 6.02x10-1 mol

Question

Kc at 25 degrees c for reaction a+b=ab. If 4.28x10-6 mol of a and 6.02x10-1 mol of b are introduced into 4 Liter vessel at 25 degree c. what is the equilibrium concentration of ab Kc at 25 degrees c for reaction a+b=ab. If 4.28x10-6 mol of a and 6.02x10-1 mol of b are introduced into 4 Liter vessel at 25 degree c. what is the equilibrium concentration of ab Kc at 25 degrees c for reaction a+b=ab. If 4.28x10-6 mol of a and 6.02x10-1 mol of b are introduced into 4 Liter vessel at 25 degree c. what is the equilibrium concentration of ab

Explanation / Answer

a+b ----> ab

mol of a = 4.28x10-6

mol of b = 6.02x10-1 , moles of a is less compared to moles of b then the formation of ab depends on the moles of a.

then equilibrium concentration of ab = 4.28x10-6/ 4 = 1.07 X 10-6 M

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