Question 1 of 12 Map coa sapling learning Two samples of sodium chloride were d

Question

Question 1 of 12 Map coa sapling learning Two samples of sodium chloride were d 1.75 g of sodium and 2.70 g of chlorine. Which of the following could be the results of the decomposition of the other sample, being consistent with the law of constant composition (also called the law of definite proportions or law of definite composition)? d into their constituent elements. One sample produced 4.83 g of sodium and 14.0 g of chlorine 4.83 g of sodium and 7.44 g of chlorine 4.83 g of sodium and 1.14 g of chlorine 0 4.83 g of sodium and 3.86 g of chlorine

Explanation / Answer

No of moles of Na = 1.75/23 = 0.0761 mole

no of moles of Cl = 2.7/35.5 = 0.0761 mole

so that, the other sample must have 1:1 ration of Na,Cl.

No of moles of Na = 4.83/23 = 0.21 mole

No of moles of Cl = 0.21 mole

mass of Cl = 0.21*35.5 = 7.455 grams

answer : 4.83 g of Na , 7.44 grams of Cl

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