An unknown aqueous solution of 9-aminoacridine in water leads to an intensity of

Question

An unknown aqueous solution of 9-aminoacridine in water leads to an intensity of fluorescence which, measured at 456 nm, is of 60% with respect to an external reference. A standard solution of this compound, the concen- tration of which is 0.1 ppm in the same solvent, leads to a fluorescence of 40%, under the same conditions. Water alone, equally under the conditions of the experiment, presents a negligible fluorescence. 1. Calculate the ppb concentration of 9-aminoacridine in the unknown sample. 2. For quantitative analysis, how can one avoid confusing the Raman diffusion and the fluorescence of the compound?

Explanation / Answer

Solution :-

0.1 ppm solution gives 40 % fluorescence

tehrefore 60 % * 0.1 ppm /40 % = 0.15 ppm

Now lets convert the ppm to ppb

0.15 ppm * 1000 ppb / 1 ppm = 150 ppb

So the concetration is 150 ppb

To avoid the Raman diffusion and fluoresensce one can select the best laser beam with specific wavelength so that the fluorosensce can be obsrved in the visible range.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.