0 10/21/2015 11:55 PM O 75.2/100 Gradebook Print Calculator Periodic Table Quest

Question

0 10/21/2015 11:55 PM O 75.2/100 Gradebook Print Calculator Periodic Table Question 7 of8 Mapoob sapling learning A solution containing the following was prepared: 0.13 M Pb2, 1.5 x106 M Pb4, 1.5 x10 M Mn2, 0.13 M MnO4, and 0.87 M HNO3. For this solution, the following balanced reduction half-reactions and overall net reaction can occur E.-1.690 v E1.507 v 4+ A) Determine Ecell. AG®, and K for this reaction. Number Number Number B) Calculate the value for the cell potential, Ecel, and the free energy, AG, for the given conditions Number Number Scroll down to answer all parts of this question. (A through D) cell O Previous 1"S Give Up & View Solution th lue. Previous Give Up &View; Solution Check Answer NextExit e Check Answer Next Exit Hint

Explanation / Answer

A) Eo=1.69-1.507
=0.183 V

DGo = -nFEo
=-10*96500*0.183
=-176.595 kJ

K=e^(-DGo/RT)
=9.047*10^30

B)K=[Pb2+]^5*[MnO4-]^2*[H+]^16/([Pb4+]^5*[Mn2+]^2)
=0.13^5*0.13^2*0.87^16/((1.5*10^-6)^5*(1.5*10^-6)^2)
=3.956*10^33

Ecell = RTln(k)/nF
=8.313*298*ln(3.956*10^33)/(10*96500)
=0.198

DG=-RTln(K)
=-1.916*10^5 J

C) At equilibrium, K=1
hence Ecell=0
D)[H+] be x.so,

1=0.13^5*0.13^2*x^16/((1.5*10^-6)^5*(1.5*10^-6)^2)
or [H+]= 0.00691337
so pH=2.16

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