Nitrogen and hydrogen gases react to form ammonia gas via the following reaction

Question

Nitrogen and hydrogen gases react to form ammonia gas via the following reaction: N2(g)+3H2(g)-->2NH3(g) At a certain temperature and pressure, 1.4 L of N2 reacts with 4.2 L of H2. If all the N2 and H2 are consumed, what volume of NH3, at the same temperature and pressure, will be produced? Nitrogen and hydrogen gases react to form ammonia gas via the following reaction: N2(g)+3H2(g)-->2NH3(g) At a certain temperature and pressure, 1.4 L of N2 reacts with 4.2 L of H2. If all the N2 and H2 are consumed, what volume of NH3, at the same temperature and pressure, will be produced? Nitrogen and hydrogen gases react to form ammonia gas via the following reaction: N2(g)+3H2(g)-->2NH3(g) At a certain temperature and pressure, 1.4 L of N2 reacts with 4.2 L of H2. If all the N2 and H2 are consumed, what volume of NH3, at the same temperature and pressure, will be produced? N2(g)+3H2(g)-->2NH3(g) At a certain temperature and pressure, 1.4 L of N2 reacts with 4.2 L of H2. If all the N2 and H2 are consumed, what volume of NH3, at the same temperature and pressure, will be produced?

Explanation / Answer

mol N2= Px1.4/RxT= Kx 1.4

mol H2=Px1.4/RxT= K x 4.2

K is a constant made by P/RT.

All the reagents are consumed so there is not a limiting reagent, we can take any of them to do the calcualtions. Let´s take N2.

1 mol N2 ------------ 2 mol NH3

(Kx1.4) mol N2 --------- x= (K x 2.8) mol NH3

V= (Kx2.8) x R x T/P= ((P/RT) x 2.8) x R x T/P = 2.8 L

It is a little complicated, let me know if you have any doubt! :)

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