1. Ignoring any side reactions and assuming the reaction occurs completely, how

Question

1. Ignoring any side reactions and assuming the reaction occurs completely, how large (in kg) an oxygen candle (KClO3) would be needed to supply 8 people with enough oxygen for 24 hours on a small submarine? Although this depends on the size of the person and their respiration rate (activity), according to NASA, an average person needs about 0.84 kg of O2 per day.

2. At 1 atmosphere and 25 o C, what would the volume of O2 be from the previous question?

3. Assuming that air is 21% O2 by volume, what volume of air would be needed to answer question 2?

4. Assuming all of the analogous reactions occur, why would lithium chlorate be a more practical choice for the “chlorate candle” than either sodium or potassium chlorate?

I just need answer to question number 3.

Explanation / Answer

2MClO3 2MCl + 3O2

90 g of LiClO3, 106 g of NaClO3 or 123 g KClO3 give 48 g of O2 so weight for LiClO3 gives more O2 per gram an important point when probably there are hundreds of pounds on board a sub for emergency purposes. It is found to be less dense and may take up more space. Note LiClO3 also dissolved at a lower Temperature than NaClO3. It was for the same reason that Apollo missions employed LiOH to absorb CO2 and not NaOH)

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