In a GC-separation of a mixture of three compounds consisting of 1 mol A, 1 mol

Question

In a GC-separation of a mixture of three compounds consisting of 1 mol A, 1 mol B, and 1 mol C, the peak area (integral) produced by the response of the detector is:

Compound A: 20 Compound B: 40 Compound C: 10

The separation of a second mix of the same compounds with an unknown composition leads to the following peak areas:

Compound A: 20 Compound B: 100 Compound C: 10

Please calculate the response ratio of your compounds if you choose compound B as your standard. What is the molar composition of the second mixture (show your calculations)?

Explanation / Answer

response ratio for sample 1.

Compound A (40/20) : compound B (40/40) : compound C (40/10)

Compound A (2) : compound B (1) : compound C (4)

response ratio for sample 2.

Compound A (100/20) : compound B (100/100) : compound C (100/10)

Compound A (5) : compound B (1) : compound C (10)

molar composition of the second mixture

We have an area of 40 for 1 mol of compound B

so area of 100 would be for = 100 x 1/40 = 2.5

we have area of 20 for 1 mol of compound A

Which remains the same in sample 2

compound C mole must also be same in sample 2 with same area

So, molar composition of second sample would be,

compound A (1 mole) : compound B (2.5 mol) : compound C (1 mol)

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