For the following reaction between Mohr\'s salt (iron as FeSO 4 (NH 4 ) 2 SO 4 *

Question

For the following reaction between Mohr's salt (iron as FeSO4(NH4)2SO4*6H2O) and potassium dichromate (dicromate as K2Cr2O7), determine the volume (in milliliters) of a 0.260 M solution of Mohr's salt that is needed to react with 0.600 L of 0.260 M potassium dichromate. (The reaction is shown in its ionic fomr in the presence of a strong acid.)

Cr2O2-7 + 6Fe2+ + 14H+ --> 2Cr3+ + 6Fe3+ + 7H2O

Mohr's salt volume =

For the same reaction, what volume (in milliliters) of 0.260 M potassium dichromate is required to fully react with 0.600 L of a 0.260 M solution of Mohr's salt?

potassium dichromate volume =

Explanation / Answer

part A )

Cr2O2-7 (potassium dichromate)+ 6Fe2+ (Mohr's salt) + 14H+ --> 2Cr3+ + 6Fe3+ + 7H2O

molarity of mohr's salt M1= 0.260 M

moles of mohr's salt n1 = 6

volume of mohr salt mohr's salt V1= ?

molarity of potassium dichromate M= 0.260 M

moles of potassium dichromate n2 = 1

volume of potassium dichromate V2= 0.600 L

M1 V1 / n1 = M2 V2 /n2

0.260 x V / 6 = 0.260 x 0.6 / 1

V = 3.6 L = 3600 ml

Mohr's salt volume =3600 ml

part B)

same above formula

0.6 x 0.260 / 6 = 0.260 x V2 / 1

V2 = 0.1 L = 100 ml

potassium dichromate volume = 100 ml

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.