Write the balanced equation. Since the amounts of 2 reclaim arc given, this is l

Question

Write the balanced equation. Since the amounts of 2 reclaim arc given, this is limiting reclaim problem. To limit (he volume of SO 2. use the molar ratios frown the balanced equation to find the number of moles of SO 2 produced by each reactant. The smaller number of moles of product indicates the limiting reactant Solve few moles of S02 using the ideal gas law. Where it comes to rest. A rod of mass M and length L can rotate about a hinge at its left end and is initially at rest. A putty ball of mass m, moving with speed v, strikes the rod at angle 6 from the normal at a distance D = 2/3 L from the point of rotation and sticks to the rod after the collision. Randomized Variables M= 3.35 kg L = 1.25 mm = 55 g v = 4.01 m/s theta= 51 degree What is the initial angular momentum of the ball, in kilogram meters squared per square second? What is the total moment of inertia If with respect to the hinge, of the rod-ball-system after the collision, in terms of the variables from the problem statement? A 2000-litre capacity tank initially contains 20kg of .sugar dissolved in 1000 liters of water - At time t = 0. pine water is added at a rate of 50 liters/min and the mixed solution is drained off at. The rate of 25 liters/min. Set up the initial value problem for the amount of sugar in the tank at. time t Find the amount of sugar in the tank when is the limiting reagent because it forms less S02. Finding the volume of S02: unknown n T- 0 degree C 273 - 273 K it replant: Write the balanced equation. Since the amounts of 2 reclaim arc given, this is a limiting reclaim problem. To limit (he volume of SO 2. use the molar ratios frown the balanced equation to find the number of moles of SO 2 produced by each reactant. The smaller number of moles of product indicates the limiting reactant Solve few moles of S02 using the ideal gas law. Moles of oxygen: aches the point of overflowing.

Explanation / Answer

Here, 0.0821 is the universal gas constant which is used commonly during the ideal gas equation calculations.

The ratio 2 mol SO2 / 3 mol O2 is obtained from the stoichiometric reaction.

2Pb+ 3O2 -------> 2PbO +2SO2

3mol O2 = 2mol SO2

2 mol SO2 / 3 mol O2 =1

It is used as conversion factorin order to convert the mole of O2 into SO2.

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