A propanol (p^*1 = 20.9 torr at 25 degree C) and 2-propanol (p^*2 = 45.2 torr at

Question

A propanol (p^*1 = 20.9 torr at 25 degree C) and 2-propanol (p^*2 = 45.2 torr at 25 degree C) form ideal solutions in all proportions. Let x_1 and x_2 represent the mole fractions of 1-propanol and 2-propanol, respectively, in a liquid mixture and y_1 and y_2 represent the mole fractions of each in the vapor phase For a solution of these liquids with x_1 = 0.700, calculate the composition of the vapor phase at 25 degree C if the vapor above the liquid phase is composed only of 1-propanol and 2-propanol.

Explanation / Answer

pressure is directly proportional to the number of moles.

so,

x1=0.7, x2=0.3

C1=k*P1

or 0.7 = 20.9*P1

or P1=0.0335

for the second solution,

C2=k2*P2

or P2=0.3/45.2

=0.006637

so y1=0.0335/(0.0335+0.006637)

=0.8346

y2=1-y1

=0.1654

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