I need some help with these double displacement reactions and their COMPLETE AND

Question

I need some help with these double displacement reactions and their COMPLETE AND NET IONIC EQUATIONS. I understand percipitates and swtiching the cations and anions, and etc. BUT I'm having some trouble with some equations. I have two example problems. I'm having troube because I don't understand what to do/what to write when the products are all soluble?

1) NiCl2 + BaCl2 --> ....???

I'm confused on #1 because both the anions are Cl? So I need help for molecular equation, complete ionic, and net ionic equations.

2) NiCl2 + Na2SO4 --> NiSO4 + 2NaCl

#2 I just need help with complete ionic and net ionic. NiSO4 is soluble so I don't know what to write for my ionic equations.

Explanation / Answer

NiCl2 (aq) + BaCl2 (aq) --- > No reaction since both are having same anions.

2).

NiCl2 (aq) + Na2SO4 (aq) --> NiSO4 (aq) + 2NaCl (aq)

Lets write total ionic equation

Ni2+ (aq) + 2Cl- (aq) + 2Na+(aq) + SO42- (aq) --> Ni2+ (aq) + 2Cl- (aq) + 2Na+(aq) + SO42- (aq)

Net ionic equation:

Here we cancel the spectator ions.

Actually all of the ions present in the total ionic equation are cancelled so there is not net reaction

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