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The amount of air that reenters the flask is different than that which was prese

ID: 898610 • Letter: T

Question

The amount of air that reenters the flask is different than that which was present upon initial weighing and subsequently expelled from the flask, due to the fact that the liquid you used was a volatile one and will not completely recondense. Some of the liquid remains in the vapor phase, even at room temperature. Given this information, is the amount of air that reenters greater or less than that which was present upon initial weighing? If you were able to correct for the difference, would your final molar mass value be greater or less than the value you determined? Explain your reasoning.

Trial Number

Final Mass

Initial Mass

Mass of Liquid (final – initial)

Molar Mass

Trial 1

82.288 g

82.242 g

0.046 g

149 mL

11.05 g/mol

Trial 2

82.305 g

82.242 g

0.063 g

150 mL

15.14 g/mol

Trial 3

82.297 g

82.242 g

0.055 g

150 mL

13.22 g/mol

Trial Number

Final Mass

Initial Mass

Mass of Liquid (final – initial)

Molar Mass

Trial 1

82.288 g

82.242 g

0.046 g

149 mL

11.05 g/mol

Trial 2

82.305 g

82.242 g

0.063 g

150 mL

15.14 g/mol

Trial 3

82.297 g

82.242 g

0.055 g

150 mL

13.22 g/mol

Explanation / Answer

Since some of the liquid has evaporated and will not condense, the amount og gas that enetrs has to be less than what goes out because at any time pressure due to gas can't exceed the initial pressure. Or you can say that number of moles of gases to be the same, less moles of gas will reeneter than came out

Since mass of container will decrease due to decrease in gaseous molecule, the molar mass taht you calculate will be less than initial

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