The amount of air that reenters the flask is different than that which was prese
ID: 898610 • Letter: T
Question
The amount of air that reenters the flask is different than that which was present upon initial weighing and subsequently expelled from the flask, due to the fact that the liquid you used was a volatile one and will not completely recondense. Some of the liquid remains in the vapor phase, even at room temperature. Given this information, is the amount of air that reenters greater or less than that which was present upon initial weighing? If you were able to correct for the difference, would your final molar mass value be greater or less than the value you determined? Explain your reasoning.
Trial Number
Final Mass
Initial Mass
Mass of Liquid (final – initial)
Molar Mass
Trial 1
82.288 g
82.242 g
0.046 g
149 mL
11.05 g/mol
Trial 2
82.305 g
82.242 g
0.063 g
150 mL
15.14 g/mol
Trial 3
82.297 g
82.242 g
0.055 g
150 mL
13.22 g/mol
Trial Number
Final Mass
Initial Mass
Mass of Liquid (final – initial)
Molar Mass
Trial 1
82.288 g
82.242 g
0.046 g
149 mL
11.05 g/mol
Trial 2
82.305 g
82.242 g
0.063 g
150 mL
15.14 g/mol
Trial 3
82.297 g
82.242 g
0.055 g
150 mL
13.22 g/mol
Explanation / Answer
Since some of the liquid has evaporated and will not condense, the amount og gas that enetrs has to be less than what goes out because at any time pressure due to gas can't exceed the initial pressure. Or you can say that number of moles of gases to be the same, less moles of gas will reeneter than came out
Since mass of container will decrease due to decrease in gaseous molecule, the molar mass taht you calculate will be less than initial
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