To solve stoichiometry problems, you must always calculate numbers of moles. Rec

Question

To solve stoichiometry problems, you must always calculate numbers of moles. Recall that molarity, M, is equal to the concentration in moles per liter:M=mol/L.

When solutions of silver nitrate and potassium chloride are mixed, silver chloride precipitates out of solution according to the equation

AgNO3(aq)+KCl(aq)AgCl(s)+KNO3(aq).

Part A What mass of silver chloride can be produced from 1.43 L of a 0.288 M solution of silver nitrate? Express your answer with the appropriate units.

mass of AgCl=

Part B The reaction described in Part A required 3.15 L of potassium chloride. What is the concentration of this potassium chloride solution?

Express your answer with the appropriate units.

Explanation / Answer

AgNO3(aq)+KCl(aq)AgCl(s)+KNO3(aq).

1 mol of silver nitrate produces 1 mol of AgCl.

mass of AgNO3 reacting=>

molar mass= 170 g/mol

mass of 0.288 Moles=0.288x170 = 49 g

mass present in 1.43 L = 1.43x49 = 70.01 g

therefore mass produced of AgCl=70.01 g

part B

molar mass of KCl=74.5 g

according to the stoichiometric coefficients, the mass of AgNO3 and KCl are equal. therefore mass of KCl= 70 g

no. of moles= 70/74.5= 0.94 moles

no. of moles in 1 L=0.94/3.15 *1 = 0.298 moles

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