KHC 8 H 4 O 4 is commonly used to standardize solutions of bases. The hydrogen p

Question

KHC8H4O4 is commonly used to standardize solutions of bases. The hydrogen phthalate anion reacts with the hydroxide ion according to the following netic ionic reaction.

HC8H4O4- (aq) + OH- (aq) --> C8H4O42- (aq) + H2O (l)

write the balanced, complete molecular reaaction between potassium hydrogen phthalate and NaOH below

If 0.902 grams of potassium hydrogen phthalate are titrated with NaOH solution, requiring 26.45ml of the NaOH solution to reach the equivalence point, what is the molarity of the NaOH solution?

Explanation / Answer

KHC8H4O4 (aq) + NaOH (aq) --> NaKC8H4O4 (aq) + H2O (l)

Now from law of milliequivalence

N1V1 = N2V2

(W / EW)1000 = N2V2

N2 = normality of NaOH = ?

V2 = Volume of NaOH = 26.45ml

W = weight of potassium hydrogen phthalate = 0.902 g

EW = Equivalent weight of potassium hydrogen phthalate = molecular weight / 1 = 204.22 /1 = 204.22

(0.902/204.22)1000 = N2 * 26.45

N2 = 0.167N

Since molarity = normality for NaOH

Concentration of NaOH = 0.167 M

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