oo Sprint Wi-Fi 8:44 AM Files Grignard.pdf Pre-Lab Assignment Grignard Reaction
ID: 899379 • Letter: O
Question
oo Sprint Wi-Fi 8:44 AM Files Grignard.pdf Pre-Lab Assignment Grignard Reaction 1. Draw your complete reaction, including the formation of the Grignard reagent and the reaction with your carbonyl compound. Below each reagent, write its mollecular weight and density (if a liquid). Also write how much of each material you will use in mL [if liquid], grams, and moles. Also include the molecular weight and melting point of your final product. 2. How many moles of Grignard reagent are you synthesizing? What mass of water could fully react with that amount of Grignard reagent? What volume of water would that be? 3. Step 11 of the procedure is called trituration and is used to extract any nonpolar impurities from your crude product (petroleum ether is a miture of different isomers of pentanes, hexanes, and heptanes). Considering the possible side reactions that can occur, draw the structure of the likely non-polar side product that you are removing in this step? Courses Calendar Todo Notifications MessagesExplanation / Answer
1. Reactions, and data table for each experiment
a) PhBr + Mg -------> PhMgBr + Benzophenone -----> (Ph)3COH
moles 1.25 1.35 1.25 1.0 1.0
molar mass 157.0079 24.305 181.31 182.217 260.33
density(g/cm^2) 1.5 - 1.14 1.11 1.20
grams 196.26 32.81 226.64 182.217
volume 130.84 - 198.80 164.16
Amount of water that it reacts with : 1.25 mols x 18 g/mol = 22.5 g = 22.5 ml
b) PhBr + Mg -------> PhMgBr + Benzaldehyde -----> (Ph)2CHOH
moles 1.25 1.35 1.25 1.0 1.0
molar mass 157.0079 24.305 181.31 106.121 m.p. 69 oC
density(g/cm^2) 1.5 - 1.14 1.04 184.23
grams 196.26 32.81 226.64 106.121 1.103
volume 130.84 - 198.80 1102.04
Amount of water that it reacts with : 1.25 mols x 18 g/mol = 22.5 g = 22.5 ml
c) PhBr + Mg -------> PhMgBr + ethylbenzoate -----> (Ph)3COH
moles 2.5 2.7 2.5 1.0 1.0
molar mass 157.0079 24.305 181.31 150.17 m.p. 162 oC
density(g/cm^2) 1.5 - 1.14 1.05
grams 392.52 65.62 453.27 150.17
volume 261.68 - 397.61 143.02
Amount of water that it reacts with : 2.5 mols x 18 g/mol = 45.05 g = 45.05 ml
2) Given below in the data table the mole of PhMgBr forming in each case. the mass equivalent to it.
The amount of water in both g and ml that will react with each grignard reagent.
3) In each case the nonpolar product isolated would be C6H6 after reaction of PhMgBr with H2O
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.