The following pedigree is (i) showing which type of genetic pattern: (ii) what i
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The following pedigree is (i) showing which type of genetic pattern: (ii) what is probability that the child indicated by"?" will be affected by the trait? There are two mechanisms for transposition used by bacterial transposable elements: replicative (Tn3) and non-replicative (Tn5 and Tn10). Compare and contrast the two mechanisms with respect to: a. Host DNA sequences adjacent to the ends of the element: b. Formation of co-integrants: c. Resolvase enzyme: d. Requirement for DNA synthesis: e. Structure of DNA in intermediates of the reaction:Explanation / Answer
33. This pedigree chart shows the parents and their offspring’s genetic relation. (i) Genetic inheritance pattern can be calculated from the pedigree as knowing the trait type.
First of all this is an example of recessive trait. As the early parents are not carrying the traits, still it si carried to the family is a feature of recessive character. Second part of determination is, weather it is a autosomal or sex-linked.
Here more number of males are affected, a heterozygous mother has produced approximately half of the affected individual. All these signs could be seen in Sex-linked recessive characters.
(ii) As the child's parents are the carriers, but they have not shown any visible change in the phenotype. In this case they could bring forward the characteristics and the probability could be 50%. As the mother and father is a carrier for the X-linked recessive gene. They could pass it to their son, if he is born. As the X gene is recessive here, so there could be XY for male and the chances will be high as 50%.
34. Replicative transposition is a mechanism where first it is replicated and then one of the copy is transferred to a new site to be integrated.
In case of non-replicative form, here the movement of a transposon leaves the donor site, by breaking its double bond and goes to a new site to be incorporated.
a) The replicative form replicates its DNA sequence, and inserted it into the host DNA by creating a nick or cut. Then the distance between the cleavage site in the target host cells sequence is equals the length of the target site, when the duplication is done. Here the DNA will have the same number of sequence, only thing is the terminal sequences are from the donor cells.
While the non-replicative form cuts the DNA transposable element from the donor DNA and then goes and binds to the host cell DNA by just forming a nick, this does not changes any sequence of nucleotides in the host DNA.
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