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13.a) Predict the number of subshells in the fourth shell, that is, for n=4. b)

ID: 900970 • Letter: 1

Question



13.a) Predict the number of subshells in the fourth shell, that is, for n=4.
b) Give the label for each of these subshells.
c) How many orbitals are in each of these subshells? Write each orbital number (ml) for each subshells.
14. [Ne] 3s2 3p3 is the electron configuration of _____ atom.
15. All of the alkaline metals have a valence shell electron configuration _____.
16. At maximum, a d-subshell can hold ____ electrons.
17. The complete electron configuration of sulfur, element 16, is ____.
18. The angular momentum quantum number for the outermost electrons in a manganese atom in the ground state is ___.
19. The electron configuration of the valence electrons of an atom in its ground state is ns2 np3. This atom is a group _____ element.
20. What is this element (1s2 2s2 2p3)?

11. The n-2t0-6 transition in the Botr hydrngen counds io the a of a photon wiâh a wavelength of b) m (Total 6 points) Is this transtion of energy state ahorpism of photon or emissin of photon? points) s) b) Caleulase the corresponding wavelength() of photon; nm-10"m (use Rydberg equat ion below) (4 poirts) 12. The lowest orhital enengy is reached when the number of electrons with the same spin is maximized. This statement describes - (1 poim)

Explanation / Answer

11. upload a better photo or transcribe it in another question

12. Hund's rule

13.   a. The number of subshells in any given shell is equal to that shell's number. Fourth shell (n=4) contains 4 subshells.

        b. 4s, 4p, 4d, and 4f

        c. 4s=one orbital 0; 4p= 3 orbitals -1 0 1; 4d= 5 orbitals -2 -1 0 1 2; 4f= 7 orbitals -3 -2 -1 0 1 2 3

14. Phosphorus

15. ns1

16. 10, 2 by every orbital (it has 5 orbitals)

17. [Ne] 3s2 3p4 or 1s2 2s2 2p6 3s2 3p4

18. 3d5 this is the last Chargeable orbital of manganese so, the angular momentum (Azimuthal) quantum number is 2, because the last orbital charged is d.

19. np3 tells you the answer: 5A or Pnictogens

20. A total of 7 electrons so the atomic number is 7 = Nitrogen

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