***Part1: Balance the following chemical equation using the lowest possible whol

Question

***Part1: Balance the following chemical equation using the lowest possible whole number coefficients. (Enter coefficients of one - blanks will be marked incorrect.)

( )CO2 + ( )H2O ( ) CH4 + ( )O2

( )Co(NO3)3 +( ) (NH4)2S ( )Co2S3 +( ) NH4NO3

( ) NH3 + ( )O2 ( )NO + ( )H2O

( ) NaCl + ( )H2SO4 ( ) Na2SO4 + ( )HCl

***Part2 : Consider the complete combustion of 2.91×10-4 moles of C6H12O6 with excess oxygen.

A. Balance the following chemical equation using the lowest possible whole number coefficients. (Enter coefficients of one - blanks will be marked incorrect.)

( ) C6H12O6 + ( )O2   ( )CO2 + ( )H2O

B. How many moles of water are produced in this reaction? [ ]

***Part3 : Determine the mass of carbon dioxide (in g) produced from the complete combustion of 8.34×10-1 g of C8H14O with excess oxygen.

[ ]

Explanation / Answer

***Part1: Balance the following chemical equation using the lowest possible whole number coefficients. (Enter coefficients of one - blanks will be marked incorrect.)

( 1 )CO2 + ( 2 )H2O ( 1 ) CH4 + ( 2 )O2

( 2 )Co(NO3)3 +( 3 ) (NH4)2S ( 1 )Co2S3 +( 6 ) NH4NO3

( 4 ) NH3 + ( 5 )O2 ( 4 )NO + ( 6 )H2O

( 2 ) NaCl + ( 1 )H2SO4 ( 1 ) Na2SO4 + ( 2 )HCl

***Part2 : Consider the complete combustion of 2.91×10-4 moles of C6H12O6 with excess oxygen.

A. Balance the following chemical equation using the lowest possible whole number coefficients. (Enter coefficients of one - blanks will be marked incorrect.)

( 1 ) C6H12O6 + ( 9 )O2   ( 6 )CO2 + ( 6 )H2O

B. How many moles of water are produced in this reaction? [ ]

2.91×10-4 moles of C6H12O6

(2.91×10-4)*6 moles of H"O = 0.001746

***Part3 : Determine the mass of carbon dioxide (in g) produced from the complete combustion of 8.34×10-1 g of C8H14O with excess oxygen.

[ ]

( 1 ) C6H12O6 + ( 9 )O2   ( 6 )CO2 + ( 6 )H2O

1 mol of carb will give you 6 mol of CO

MW of C6H12O6 = 180

mol = mass/MW = 8.34*10^-1 / (180) = 0.00463 mol of C6H12O6

expect 6 times that of CO2

6*0.00463 = 0.0278 mol of CO2

MW CO2 = 44

mass = mol*MW = 44*0.0278 = 1.2232 grams of CO2

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.