11/1/2015 11:55 PM A 7o/100 Gradebook Print Calculator Periodic Table Question 2

Question

11/1/2015 11:55 PM A 7o/100 Gradebook Print Calculator Periodic Table Question 22 of 25 Organic Chemistry Roberts & Company Publishers presented by Sapling Leaming Marc Loudon The standard free energy of activation of a reaction A is 88.2 kJ mo 1 (21.1 kcal mol at 298 K. Reaction B is one million times faster than reaction A at the same temperature. The products of each reaction are 10.0 kJ mol 1 (2.39 kcal mo 1) more stable than the reactants (a) What is the standard free energy of activation of reaction B? Number kJ mol (b) What is the standard free energy of activation of the reverse of reaction A? Number kJ mol (c) What is the standard free energy of activation of the reverse of reaction B? Number kJ mol Previous Give Up & View Solution Check Answer Next Exit Hint

Explanation / Answer

G=HTS

b) EaForward - Eabackward = H

   88.2 -Eabackward = -10

    Eabackward = -98.2 Kj/mol

b) k2/k1 = e-H/RT

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.