1st and 2nd Trial- 1mL of Amylase (.05%) 1mL of Starch (.30 wt%) 3mL of Buffer (

Question

1st and 2nd Trial-
1mL of Amylase (.05%)
1mL of Starch (.30 wt%)
3mL of Buffer (4.5-5.5 pH)
All added to 20 mL of Water

3rd Trial-
2mL of Amylase
1mL of Starch
2mL of Buffer
All added to 20 mL of Water

4th Trial-
1mL of Amylase
2mL of Starch
2mL of Buffer
All added to 20 mL of water

Total volume of reaction solution in Trials 1 and 2: 25 mL Concentration of starch in pipette for all Trials: 30 wt% Concentration of Amylase in pipette for all Trials: wt% Conc. of starch in reaction flask, Trials 1 and 2: 012 wt% Conc. of amylase in reaction flask, Trials 1 and 2: wt% Total volume of reaction solution, Trials 3 and 4: 25 mL Conc. of starch in reaction flask, Trial 3: 012 wt% Conc. of amylase in reaction flask, Trial 3: wt% Conc. of starch in reaction flask, Trial 4: 024 wt%

Explanation / Answer

1mL of Amylase (.05%)
1mL of Starch (.30 wt%)
3mL of Buffer (4.5-5.5 pH)
All added to 20 mL of Water so now new volume will be 20+3+1+1 = 25mL

1) Total volume = 25 mL

2) Concentration of starch in pipette = 0.30%

3) Concentration of Amylase = 0.05%

4) Concentration of starch in reaction flask 1 and 2

we have 1mL of Amylase (.05%) 1mL of Starch (.30 wt%) 3mL of Buffer (4.5-5.5 pH) in reaction flask of total 25ml solution

0.30% means 0.30g in 100ml, which means 0.003g in 1ml, and it is getting diluted to 25ml

so now 0.003g in 25 ml so concentration will be 0.003/25 * 100 = 0.012%

5) Concentration of amylase in reaction flask 1 and 2

we have 1mL of Amylase (.05%) 1mL of Starch (.30 wt%) 3mL of Buffer (4.5-5.5 pH) in reaction flask of total 25ml solution

0.05% means 0.05g in 100ml, which means 0.0005g in 1ml, and it is getting diluted to 25ml

so now 0.0005g in 25 ml so concentration will be 0.0005/25 * 100 = 0.002%

similarly you can do rest (4 questions per one set can be answered)

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